📘 Chapter 3: Rank–Nullity Theorem

📖 Theorem Statement

Let \( T: V \rightarrow W \) be a linear transformation between finite-dimensional vector spaces. Then:

\[ \dim(\ker(T)) + \dim(\text{Im}(T)) = \dim(V) \]

This is known as the Rank–Nullity Theorem, where:

🧠 Sketch of the Proof

The theorem relies on choosing a basis for the kernel and extending it to a basis for the domain space. Applying \( T \) to the extended basis yields a basis for the image.

🚀 Applications

📊 Example

Let \( A = \begin{bmatrix} 1 & 2 & 3 \\ 0 & 1 & 4 \end{bmatrix} \) - Domain dimension = 3 (number of columns) - Row reduce to find Rank = 2 - So Nullity = \( 3 - 2 = 1 \)

\[ \text{Rank}(A) + \text{Nullity}(A) = 2 + 1 = 3 = \text{dimension of domain} \]

📝 Practice

Q: A \( 4 \times 5 \) matrix has rank 3. What is its nullity?

Answer: Nullity = \( 5 - 3 = 2 \)