📘 Chapter 3: Rank–Nullity Theorem
📖 Theorem Statement
Let \( T: V \rightarrow W \) be a linear transformation between finite-dimensional vector spaces. Then:
\[ \dim(\ker(T)) + \dim(\text{Im}(T)) = \dim(V) \]This is known as the Rank–Nullity Theorem, where:
- \( \dim(\ker(T)) \) = Nullity of \( T \)
- \( \dim(\text{Im}(T)) \) = Rank of \( T \)
🧠 Sketch of the Proof
The theorem relies on choosing a basis for the kernel and extending it to a basis for the domain space. Applying \( T \) to the extended basis yields a basis for the image.
🚀 Applications
- Determining if a matrix has a full-rank transformation
- Analyzing solutions to systems of equations
- Understanding dimensions of solution spaces
📊 Example
Let \( A = \begin{bmatrix} 1 & 2 & 3 \\ 0 & 1 & 4 \end{bmatrix} \) - Domain dimension = 3 (number of columns) - Row reduce to find Rank = 2 - So Nullity = \( 3 - 2 = 1 \)
\[ \text{Rank}(A) + \text{Nullity}(A) = 2 + 1 = 3 = \text{dimension of domain} \]📝 Practice
Q: A \( 4 \times 5 \) matrix has rank 3. What is its nullity?
Answer: Nullity = \( 5 - 3 = 2 \)